Compound Q&A

How is (2R)-2-(9H-fluoren-9-ylmethoxycarbonylamino)hex-5-enoic acid (CAS: 865352-21-2) typically synthesized?

Answer

(2R)-2-(9H-fluoren-9-ylmethoxycarbonylamino)hex-5-enoic acid
(2R)-2-(9H-fluoren-9-ylmethoxycarbonylamino)hex-5-enoic acid is typically synthesized through multistep reactions starting from fluorenylmethanol and hex-5-enoic acid, involving protection, acylation, and deprotection steps. Commonly used catalysts include strong bases like diisopropylethylamine, and the overall yield is usually around 70-80%. Selectivity for the desired stereoisomer is achieved through careful control of reaction conditions.

About

English Name (2R)-2-(9H-fluoren-9-ylmethoxycarbonylamino)hex-5-enoic acid
Molecular Formula C21H21NO4
Molecular Weight 351.4 g/mol
SMILES C=CCC[C@@H](NC(OCC1C2=C(C3=C1C=CC=C3)C=CC=C2)=O)C(O)=O
InChIKey CPJQXKHZCVDRSX-LJQANCHMSA-N
Last Updated: 2025-11-07 19:01

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