Compound Q&A
How is Methyl 6-bromo-1-isopropyl-1H-indazole-4-carboxylate (CAS: 1346702-52-0) typically synthesized?
Answer
Methyl 6-bromo-1-isopropyl-1H-indazole-4-carboxylate can be synthesized through the reaction of 1-isopropyl-1H-indazole-4-carboxylic acid with bromine in the presence of a base such as sodium hydride. The key steps involve the bromination of the free carboxylic acid group to form the corresponding bromide, followed by its esterification with methyl alcohol. The reaction yields a high purity product with good selectivity and excellent yield.
About
CAS No
1346702-52-0
English Name
Methyl 6-bromo-1-isopropyl-1H-indazole-4-carboxylate
Molecular Formula
C12H13BrN2O2
Molecular Weight
297.15 g/mol
SMILES
COC(=O)c1cc(Br)cc2c1cnn2C(C)C
InChIKey
PNWPGLSNRZLQEG-UHFFFAOYSA-N
Last Updated: 2025-12-26 02:37
