Compound Q&A

How is 2-[2-(Octadecyloxy)ethoxy]ethanol (CAS: 16057-43-5) typically synthesized?

Answer

2-[2-(Octadecyloxy)ethoxy]ethanol
2-[2-(Octadecyloxy)ethoxy]ethanol is typically synthesized via the reaction of 1,2-ethanediol with 1-dodecanol in the presence of a strong base such as sodium hydride or potassium tert-butoxide. The process involves a transesterification reaction followed by hydrolysis to form the final product. Yields are usually high, and the reaction is carried out under basic conditions to ensure the formation of the desired alcohol.

About

CAS No 16057-43-5
English Name 2-[2-(Octadecyloxy)ethoxy]ethanol
Molecular Formula C22H46O3
Molecular Weight 358.61 g/mol
SMILES CCCCCCCCCCCCCCCCCCOCCOCCO
InChIKey ILCOCZBHMDEIAI-UHFFFAOYSA-N
Last Updated: 2026-01-07 14:58

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