Compound Q&A

How is Bis(1,5-cyclooctadiene)dimethoxydiiridium (CAS: 12148-71-9) typically synthesized?

Answer

Bis(1,5-cyclooctadiene)dimethoxydiiridium
Bis(1,5-cyclooctadiene)dimethoxydiiridium (CAS: 12148-71-9) is synthesized by reacting iridium(III) chloride with 1,5-cyclooctadiene in the presence of methanol. The reaction is typically carried out under an inert atmosphere to prevent oxidation of the reducing agent. The product is usually isolated by filtration, washing, and drying. The yield is generally high, and the compound can be obtained with good purity.

About

CAS No 12148-71-9
English Name Bis(1,5-cyclooctadiene)dimethoxydiiridium
Molecular Formula C18H34Ir2O2+2
Molecular Weight 666.9 g/mol
SMILES C[OH2+].C[OH2+].C1CC=CCCC=C1.C1CC=CCCC=C1.[Ir].[Ir]
InChIKey MNKCGUKVRJZKEQ-MIXQCLKLSA-P
Last Updated: 2025-09-19 21:14

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